Finding Max & Min of r=2-2cos(\Theta)

[Ashford]

Homework Statement

Find the Maximum and Minimum of the following equation.
r=2-2cos(\Theta)

The Attempt at a Solution

Max- 2-2 cos (0\pi)=0
(0,0\pi);(0,2\pi)

Min 2-2cos(\pi)=4
(4,\pi)

Do i just have these backwards?

 

[Dick]

0<4, so yes, you have them backwards. 4 is the max, 0 is the min.

 

[HallsofIvy]

I'm wondering how you determined that

Max- 2-2 cos (0)=0
(0,0\pi[/itex\);(0,2\pi)<br /> <br /> Min 2-2cos()=4<br /> (4,\pi)

<br /> <br /> And, by the way, an <i>equation</i> does <b>not</b> have a max or min- a <i>function</i> does. An equation does not even have a &quot;value&quot; to be max or min.