- #1
x2017
- 84
- 1
Homework Statement
Homework Equations
ΣF=ma
The Attempt at a Solution
I drew a free body diagram for a), but am unsure where to go from here. Do I have enough information to rearrange the equations above and solve for FN?
In the Y direction, Fy1 & Fy2 are the forces on the pole from the athlete's hands, mg is the weight of the pole itself and FN is the force the ground exerts on the pole.haruspex said:What are all these different forces? You are making it much more complicated than it is.
You do not have any information that allows you to treat the pole and vaulter separately, nor are you asked anything that requires you to do so.x2017 said:In the Y direction, Fy1 & Fy2 are the forces on the pole from the athlete's hands, mg is the weight of the pole itself and FN is the force the ground exerts on the pole.
Okay, so is it as simple as saying that the force from the ground acting on the pole is equal and opposite to the net vertical force? So -1500N?haruspex said:You do not have any information that allows you to treat the pole and vaulter separately, nor are you asked anything that requires you to do so.
The wording is a little strange, but it says the 1500N is the vertical component of the force from the ground acting on the pole. I do not know why it emphasises or even mentions "net".x2017 said:Okay, so is it as simple as saying that the force from the ground acting on the pole is equal and opposite to the net vertical force? So -1500N?
Or should it be -1500N + mg of the pole/athlete since the mass of both together was given?
EDIT: I think my first idea is most likely correct if this is the right way to think about the problem since 1500N is the net vertical force
haruspex said:The wording is a little strange, but it says the 1500N is the vertical component of the force from the ground acting on the pole. I do not know why it emphasises or even mentions "net".
To what question is 1500N-mg an answer?x2017 said:1500N-mg?
haruspex said:To what question is 1500N-mg an answer?
haruspex said:what is the resultant force of A on B?
Yes, as vectors.x2017 said:FV + Fh?
How do you add vectors in different directions?x2017 said:So the force from the ground acting on the pole should be 1500N+700N = 2200N?
If the ground could not apply a horizontal force to the pole then the end of the pole would slide under the bar. Not very convenient for the vaulter.x2017 said:I thought the ground could only apply force to the pole vertically
haruspex said:How do you add vectors in different directions?
Yes.x2017 said:Since one is horizontal and one is vertical am I supposed to use pythagorean theorem?
The force of gravity on a pole vaulter is the same as the force of gravity on any object on Earth, which is approximately 9.8 meters per second squared.
The force needed for a successful pole vault is dependent on a variety of factors, including the speed of the vaulter, the angle of the pole, and the height of the jump. To calculate this force, you would need to use the equation F=ma, where F is the force, m is the mass of the vaulter, and a is the acceleration.
The pole is a crucial factor in determining the force during a pole vault. The flexibility and stiffness of the pole can greatly affect the amount of force needed for a successful jump. A stiffer pole will require more force to bend, while a more flexible pole will require less force.
Air resistance, also known as drag, plays a significant role in pole vaulting. As the vaulter runs with the pole, they create a displacement in the air, which creates drag. This drag force can either help or hinder the vaulter depending on the direction and speed of the wind.
The vaulter's technique is essential in determining the amount of force needed for a successful pole vault. Proper technique, such as a strong and consistent run-up, proper positioning on the pole, and a well-executed take-off, can help the vaulter generate more force and achieve a higher jump.