Pole-Zero Plot and ROC for LTI System

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The discussion focuses on analyzing the discrete-time LTI system with the transfer function H(z) = (1-3z^-1) / (2-z^-1). The pole-zero plot reveals the system's poles at z=2 and a zero at z=3. For stability, the region of convergence (ROC) must include the unit circle, while for causality, the ROC must extend outward from the outermost pole. The system can have a causal and stable inverse, and the inverse transfer function H^(-1)(z) can be determined along with its ROC. The relationship between stability, causality, and ROC is crucial for understanding the system's behavior.
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Consider a discrete-time LTI system with transfer function
H(z) =(1-3z^-1) / ( 2-z^-1)
(a) Sketch the pole-zero plot of H(z).
(b) Suppose the system is stable. Determine all possible regions of convergence (ROC) for H(z) under this condition, or state that none exists.
(c) Repeat part (b) assuming the system is causal instead of stable.
(d) Can this system have a causal and stable inverse? If so, determine
H^(-1)(z) including its ROC. If not, explain why not.
 
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hxluo said:
Consider a discrete-time LTI system with transfer function
H(z) =(1-3z^-1) / ( 2-z^-1)
(a) Sketch the pole-zero plot of H(z).
(b) Suppose the system is stable. Determine all possible regions of convergence (ROC) for H(z) under this condition, or state that none exists.
(c) Repeat part (b) assuming the system is causal instead of stable.
(d) Can this system have a causal and stable inverse? If so, determine
H^(-1)(z) including its ROC. If not, explain why not.

1.) Find the poles and zeros of H. They will be easy to see if you multiply the top and bottom by z.

2.) Find how stability and causality relate to ROC of your plot. Stability is related to the unit circle and causality is related to inside or outside of the extreme poles.

3.) Draw a pair of axes. Draw a circle centered at the origin. Use knowledge gained in steps 1 and 2 to draw the pole-zero diagram.
 
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