Police Car Overtaking Speeder: How to Calculate the Time and Distance?

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AI Thread Summary
A police car traveling at 90 km/h is overtaken by a speeder going 130 km/h, with the police accelerating 1 second later at 2.00 m/s². To solve the problem, one needs to calculate the positions of both vehicles over time using the equations for constant velocity and constant acceleration. The key is to set the equations equal to find the time at which the police car overtakes the speeder. The discussion highlights the need for guidance in applying these formulas correctly. Understanding the motion equations is essential for solving this type of problem effectively.
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Homework Statement



A police ar traveling a constant 90 km/h is passed by a speeder travelig 130 km/h. 1.00s after the speeder passes, the policeman steps on the accelerator. If the police car's acceleration is 2.00 m/s^2, how much time elapses after the police car is passed until it overtakes the speeder (assumed moving at a constant speed)



The Attempt at a Solution


This is my first encounter with these types of problems, at the level where I need to solve it without trial and error graphing.

Could someone provide a bit of guidance because I'm not sure how to do this problem.
 
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What is the position of the speeder at time t.
What is the position of the policeman at time t.
for what t are they equal.

motion with constant acceleration:
x = x_0 + v_0 t + (1/2) a t^2

motion with constant velocity
x = x_0 + v_0 t
 
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