Polyatomic ions and their charge

  • Thread starter Thread starter icefire23
  • Start date Start date
  • Tags Tags
    Charge Ions
AI Thread Summary
The discussion revolves around understanding the charges of polyatomic ions, specifically focusing on selenate (SeO4) and its charge of -2. The key point is that the charge of a polyatomic ion can be determined by analyzing the oxidation states of its constituent atoms. In the case of selenate, the overall charge results from the electron configurations and bonding of selenium and oxygen atoms. It is explained that pairing electrons to achieve stable configurations helps deduce the net charge of the ion. The conversation also highlights the importance of visualizing the bonds within the ion, such as the presence of double and single bonds between selenium and oxygen, to clarify how the charge is derived. Despite some confusion about the diagrams and concepts, the discussion emphasizes a methodical approach to understanding ion charges through electron pairing and oxidation states.
icefire23
Messages
3
Reaction score
0
This question is regarding polyatomic ions and their charge. I have always been told that I have to memorize the charge of polyatomic ions. The question is whether I can determine by myself the charge of two atoms when they join together to form a polyatomic ion. For example Se and O can form selenate SeO4, this polyatomic ion has a charge of -2. I would like to know why is the charge -2? But what I know the sum of all oxidation states of the joining ions must be equal to the net charge of the ion. But what happens then if I do not know the net charge of the ion? Hopefully these questions are not too silly. Thanks before hand, Aldo.
 
Chemistry news on Phys.org
Selenate.png


Because the ion is like this. There is 1 unpaired electrons on 2 oxygen atoms, giving it a charge of 2-.

For these kinds of ions, just try pairing up their electrons to get a stable electron configuration until you only have unpaired electrons left. You can then deduce the charge of the whole ion from that.
 
Ok, seeing the bonds in the ion helped. Thank you very much for your help. So, when I have the SeO3 anion with a charge of -2, I would have 1 Selenium Oxygen double bond and two Selenium Oxygen single bonds, with an electron pair in the Selenium? Aldo.
 
yeap.

btw, what's aldo?
 
Thanks again for your help. Hahahaha..Aldo is just my name : )
 
Bloodthunder said:
Selenate.png


Because the ion is like this. There is 1 unpaired electrons on 2 oxygen atoms, giving it a charge of 2-.

For these kinds of ions, just try pairing up their electrons to get a stable electron configuration until you only have unpaired electrons left. You can then deduce the charge of the whole ion from that.

I still don't get how SeO4 acquires a charge of 2-. I don't understand the diagram above either. Please explain in more plain language.
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top