MHB Can (I-A)^{-1} Be Expressed as a Series When A^4 = 0?

  • Thread starter Thread starter delgeezee
  • Start date Start date
  • Tags Tags
    Polynomial Proof
delgeezee
Messages
12
Reaction score
0
Let A be a square matrix,

a) show that $$(I-A)^{-1}= I + A + A^2 + A^3 if A^4 = 0$$

b) show that $$(I-A)^{-1}= I + A + A^2+...+A^n $$ if $$
A^{n+1}= 0$$
 
Physics news on Phys.org
Re: polynomial problem proof?

B is the inverse of A iff AB = BA = I
so
try
(I -A )( I + A + A^2 + A^3) = I-A + A - A^2 + A^2 - A^3 + A^3 - A^4 = I - A^4 = I
 
Thread 'Derivation of equations of stress tensor transformation'
Hello ! I derived equations of stress tensor 2D transformation. Some details: I have plane ABCD in two cases (see top on the pic) and I know tensor components for case 1 only. Only plane ABCD rotate in two cases (top of the picture) but not coordinate system. Coordinate system rotates only on the bottom of picture. I want to obtain expression that connects tensor for case 1 and tensor for case 2. My attempt: Are these equations correct? Is there more easier expression for stress tensor...
Back
Top