Pool Filling & Emptying: Calculating Capacity & Rate

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The pool has a total capacity of 1000 cubic meters and began filling on Thursday at 6 AM. After 27 hours of filling, a water removal pump was mistakenly activated, leading to both filling and emptying simultaneously. The pool was completely empty by Monday at 6 PM, indicating that the rate of water removal exceeded the filling rate. Calculations show that while the filling rate is r_1, the removal rate is r_2, with the relationship r_2 being 4/3 times r_1, but insufficient data prevents determining exact rates. The discussion concludes with a need for more information to accurately solve the problem.
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Homework Statement


The total capacity of the pool is 1000 cubic meters. the filling of the pool started on Thursday morning at 6 o’clock. On Friday morning at 9 o’clock when the pool was being filled, the pump for removal of water was started by mistake. Starting from this point onwards, water was both added and removed from the pool.
The pool became empty on Monday evening at 6 o’clock pm (18:00). It can be assumed that the rate at which the water was added and removed were both constant.

Homework Equations


a) When would the pool have been full if the pump to remove the water had not been
started? State in your answer the day of the week and the time of the day with the
accuracy of one hour. You can solve the problem graphically or mathematically.
b) How many cubic meters of water does the removing pump get rid of in 24 hours?

The Attempt at a Solution


How should we use the rate here?
we know that it was filling for 108 hours and emptying for 81 hours, But then?
 
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Seems like a piece of info is missing from the problem. There is no indication of the amount of water in the pool at a certain point in time. If we had this piece of info, we can certainly find the rates at which the water was added and removed. Are you sure this is the entire problem?
 
Yes, i copied it as it was given!
 
I second what eumyang said.

It tells us the capacity of the pool, but not at the rate it can be filled or emptied, or at what level the water was when the emptying started. Not enough info...
 
Assuming that the pool started empty, let the rate at which the first pump fills the pool be r_1 cubic feet per hour and the rate at which the second pump empties the pool be r_2 feet per hour. From 6:00 Thursday morning to 9:00 Friday morning is 27 hours so there would be 27r_1 cubic feet of water in the pool at that time. After that, with both pumps running, the water is coming in at [itexs]r_1- r_2[/itex] cubic feet per minute Since that cause the pool to eventually become empty again, r_1 must be less than r_2 so that r_1- r_2 is negative. In fact, it takes 81 hours to empty the pool so we must have 27r_1+ 81(r_1- r_2)= 108r_1- 81r_2= 0 so that 81r_2= 108r_1 so that r_2= (4/3)r_1.

But that single equation is not enough to determine r_1 and r_2 separately, which is what would be need to answer the questions.
 
HallsofIvy said:
Assuming that the pool started empty, let the rate at which the first pump fills the pool be r_1 cubic feet per hour and the rate at which the second pump empties the pool be r_2 feet per hour. From 6:00 Thursday morning to 9:00 Friday morning is 27 hours so there would be 27r_1 cubic feet of water in the pool at that time. After that, with both pumps running, the water is coming in at [itexs]r_1- r_2[/itex] cubic feet per minute Since that cause the pool to eventually become empty again, r_1 must be less than r_2 so that r_1- r_2 is negative. In fact, it takes 81 hours to empty the pool so we must have 27r_1+ 81(r_1- r_2)= 108r_1- 81r_2= 0 so that 81r_2= 108r_1 so that r_2= (4/3)r_1.

But that single equation is not enough to determine r_1 and r_2 separately, which is what would be need to answer the questions.

Oh, now we can finish answering the questions!

chawki said:
a) When would the pool have been full if the pump to remove the water had not been
started? State in your answer the day of the week and the time of the day with the
accuracy of one hour.

:wink:
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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