Positronium Decay: Find Momentum of Gamma Rays

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The discussion focuses on calculating the momentum of gamma rays resulting from positronium decay, specifically showing that it equals m_0c, where m_0 is the electron mass. The participant expresses uncertainty about whether to apply conservation of energy, momentum, or both, and questions the relevance of provided equations. They attempt to use conservation of momentum but realize they mistakenly include velocity (v) instead of the speed of light (c) in their calculations. Clarification is sought on the correct approach to derive the momentum of each gamma ray. The conversation highlights the challenges faced by individuals transitioning from mathematics to physics, particularly in understanding energy considerations.
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Homework Statement



Consider positronium decay. Show the magnitude of the momentum for each gamma ray is m_0c where m_0 is the mass of the electron.

Homework Equations



E=\sqrt{p^2c^2+m^2c^4}, p=h\nu/v

The Attempt at a Solution



I'm not sure how to start this one, though I suspect the solution is elementary. Should I use conservation of energy or momentum or both? Are the above equations relevant? I come from a mathematics background, not a physics background, so problems which require "energy considerations" still confuse me.
 
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Here's a first attempt: we use conservation of momentum and find |p_{\text{before}}|=|p_{\text{after}}| \Rightarrow 2\gamma m_0v =2\gamma h\nu / c \Rightarrow m_0v=h\nu/c = |p_i| for each gamma ray p_i where the last inequality is from a previous exercise which asks us to show this for each photon. So I end up with *almost* the solution except I have v instead of c. Where did I go wrong?
 
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