Possible that a fabric can be used as a diffraction grating

AI Thread Summary
A fabric can indeed function as a diffraction grating if the spacing between its threads is on the order of a micron, allowing for noticeable diffraction of visible light. This phenomenon occurs because light can bend when it encounters such structures, similar to traditional diffraction gratings. Additionally, the discussion touches on the concept of sound diffraction, suggesting that sound waves can travel and be heard over distances, such as hearing a neighbor shout from another house. The principles of diffraction apply to both light and sound, enabling these waves to bend around obstacles. Understanding these concepts highlights the fascinating interactions between waves and materials.
franz32
Messages
133
Reaction score
0
Is it possible that a fabric can be used as a diffraction grating where in the space between strands of threads is a small fraction of a millimeter?

My answer is yes. does it mean that the light can be bended due to this? I mean how come?
 
Physics news on Phys.org
My answer is yes
You are right.

does it mean that the light can be bended due to this? I mean how come?
In the exact same way that a diffraction grating (transmission) does. As long as the spacing is of order a micron, you will have noticeable diffraction in the visible range.
 
Last edited:
One more thing... How is it possible for those "sound waves" be heard by a person even if he's in a different house... I mean, yup, by diffraction, one can hear your neighbor shouting at your house? How would that sound travel.. in order to hear it?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top