Can You Compress a 95% Vacuum in a Sealed Cylinder?

  • Thread starter Thread starter Roger900
  • Start date Start date
  • Tags Tags
    Vacuum
AI Thread Summary
In a sealed cylinder with a 95% vacuum and a piston, once the piston is unlocked, it can be depressed to compress the remaining 5% of air. The piston will move until the pressure inside the cylinder equalizes with the atmospheric pressure outside, effectively creating a scenario similar to starting with no vacuum. After this equalization, further compression of the gas can occur, allowing for manipulation of the air volume. It is clarified that a vacuum itself cannot be compressed, as it represents the absence of matter. The discussion emphasizes understanding the behavior of gases under pressure rather than over-complicating the scenario.
Roger900
Messages
11
Reaction score
0
If a cylinder has a closed, sealed end, and the other end is a piston, and a 95% vacuum is drawn in the cylinder between the sealed end and the piston head, can the piston be depressed to "compress" the vacuum? Can the remaining 5% of air in the cylinder be compressed in any compression amount?
 
Physics news on Phys.org
Are you serious?

If you sucked 95% of the air out of the cylinder, what do you suppose the piston will want to do if you leave it to its own devices?
 
DaveC426913 said:
Are you serious?

If you sucked 95% of the air out of the cylinder, what do you suppose the piston will want to do if you leave it to its own devices?
I should have clarifed...that the piston is locked and cannot move when the vacuum is drawn on the cylinder chamber. Then, the valve to the vacuum pump is closed, leaving the 95% vacuum in the cylinder. Now, if the piston is unlocked, can the piston be depressed any amount to compress the 5% of the air remaining in the cylinder?
 
When the piston is released, it will be sucked down into the cylinder, eventually reaching a point where the pressure inside and pressure outside are equal and the piston comes to rest. It would be very possible to compress the remaining gas inside the cylinder further, after the piston is sucked down and the pressure euqalized, it would be no different than the original position the piston was in was it was a 0% vacuum.
 
As MrJ points out, you are very quickly going to have a chamber that is at 1 atm (though only 1/20th the volume it was). With your chamber of 1 atm of air, you can do whatever you want - including compress it.

Oh, and no, you *cannot* compress vacuum - it is as non-sensical as "adding some cold" to a system.

I think you are over-thinking this problem.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top