Engineering Possible to design a circuit with EXACTLY 10mA of current?

AI Thread Summary
Designing a circuit to achieve exactly 10mA of current is impractical due to inherent inaccuracies in voltage supplies and resistors, which prevent achieving precise values. Even with a perfectly accurate 1000-ohm resistor and 10 volts, variations in real-world components lead to deviations. When measuring resistance in a series-parallel circuit with an ohmmeter, it is crucial to isolate the resistor being measured to avoid interference from other components. The discussion emphasizes the challenges of achieving exact current values in practical applications. Ultimately, achieving a precise 10mA current is hindered by component tolerances and measurement limitations.
cutler
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Why isn't it possible to design a circuit with EXACTLY 10mA of current?

Also

When an ohmmeter is used to measure resistance in a series-parallel circuit, what precautions must be taken?
 
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You could get 10 mA if you had exactly 10 volts across a 100% accurate 1000 ohm resistor.
However, you can't get an exact 10 volts because all voltage supplies have some error, and all resistors are not 100 % accurate either.

You have to be sure the resistance you are measuring is only due to the resistor you want to measure. Others in parallel with it will affect the reading.
 


cutler said:
Why isn't it possible to design a circuit with EXACTLY 10mA of current?

Also

When an ohmmeter is used to measure resistance in a series-parallel circuit, what precautions must be taken?

So how about you give us your answers now, based on vk6kro's hints?
 
Thread 'Have I solved this structural engineering equation correctly?'

Thread 'Have I solved this structural engineering equation correctly?'

Hi all, I have a structural engineering book from 1979. I am trying to follow it as best as I can. I have come to a formula that calculates the rotations in radians at the rigid joint that requires an iterative procedure. This equation comes in the form of: $$ x_i = \frac {Q_ih_i + Q_{i+1}h_{i+1}}{4K} + \frac {C}{K}x_{i-1} + \frac {C}{K}x_{i+1} $$ Where: ## Q ## is the horizontal storey shear ## h ## is the storey height ## K = (6G_i + C_i + C_{i+1}) ## ## G = \frac {I_g}{h} ## ## C...
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