Possible values of p for a triangle with given angle A=45 and tanBtanC=p

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For the triangle with angle A=45 degrees and the relationship tanBtanC=p, the expression for cos(B-C) is derived as (1+p)/{(p-1)√2}. The book indicates that for valid angles B and C, which range from 0 to 135 degrees, the expression must satisfy the inequality -1/√2 < (1+p)/{(p-1)√2} <= 1. Understanding that B+C=135 degrees leads to B=135-C and helps analyze the dependency of B-C on C. The discussion emphasizes finding the range of values for p that ensure A, B, and C remain valid angles in a triangle.
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Homework Statement


Let A,B,C be three angles such that A=45 (degrees) and tanBtanC=p. Find all possible values of p such that A,B,C are the angles of a triangle.


Homework Equations





The Attempt at a Solution



I got an expression for cos(B-C)= (1+p)/{(p-1)√2}
My book says this-
Since B or C can vary from 0 to 135,
-1/√2 < (1+p)/{(p-1)√2} <= 1

I did not understand how this step came. Please help
 
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Hint: You know that B+C=135, so B=135-C and B-C=135-2C.
 
But B-C=135-2C is not independent of C.
How will that help?
 
Why should it be independent of C? Think about what range of values C can assume and what this means about range of values cos(B-C) can assume.
 
Thanks, I got it
 
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