Possible webpage title: What Remains Constant in One-Dimensional Kinematics?

AI Thread Summary
The discussion centers on the relationship between various quantities in one-dimensional kinematics, specifically focusing on the area under velocity vs. time curves. It is established that the total displacement (D) remains constant from t = 0 to t = tf, making it the correct answer. However, there is a debate about whether average velocity (B) is also constant, as it relates to total displacement over time. Clarification is provided that average velocity is only constant if the time intervals are the same for both curves. The conversation concludes with agreement on the nuances of these kinematic relationships.
yti1211
Messages
5
Reaction score
0
The area under both curves (velocity vs time) from t =0 to t =tf is the same. Which of the following quantities is the same from t =0 to t = tf?

A. average position B. average velocity C.average accerleration D. total displacement
E. jerk( the derivative of accerleration.

THE correct answer is D, but I think B and D both work, because average v = total displacement/time. so is the answer key wrong?

THANKSSSSSS
 
Physics news on Phys.org
Welcome to PF!

yti1211 said:
The area under both curves (velocity vs time) from t =0 to t =tf is the same. Which of the following quantities is the same from t =0 to t = tf?

A. average position B. average velocity C.average accerleration D. total displacement
E. jerk( the derivative of accerleration.

THE correct answer is D, but I think B and D both work, because average v = total displacement/time. so is the answer key wrong?

THANKSSSSSS

Hi yti1211! Welcome to PF! :smile:

hmm … I was going to say rubbish, you don't understand this …

but I think you're right! :biggrin:

(Unless, of course, the curves have different tfs:

D is correct even for different tfs, but B is correct only for the same tfs.)
 
haha, thanks tiny-tim! :))
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top