Potential difference(capacitor)

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The discussion clarifies that when one plate of a capacitor is at +75 V and the other at -75 V, the potential difference is 150 V, which is crucial for understanding capacitor behavior. The calculation of potential difference is based on the difference between the two voltages, hence 75 - (-75) equals 150 V. It emphasizes that the relevant voltage for capacitor equations, such as Q = C V, is the potential difference across the plates. Each plate holds equal but opposite charges, with the positive plate having charge +Q and the negative plate -Q, and the charge referenced is typically that of the positive plate. Understanding these concepts is essential for solving capacitor-related problems in physics.
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Homework Statement



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Homework Equations





The Attempt at a Solution



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1) "One plate is maintained at +75 V while the other at -75 V by a d.c. supply" means? Does it means that this capacitor is connected to a 150 V d.c. supply or just a 75 V?
2) Why is 75-(-75)? Why don't we just use 75V?
3) Charge stored on each plate is it the same as charge stored in the whole capacitor?
:confused:
 

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stpmmaths said:
1) "One plate is maintained at +75 V while the other at -75 V by a d.c. supply" means? Does it means that this capacitor is connected to a 150 V d.c. supply or just a 75 V?
All that matters with capacitors is the potential difference across the plates because that is the voltage V as in Q = C V. So you can view this as one plate being at potential 0 V and the other at 150 V or -75 V and 75 V, or 250 V and 100 V.
2) Why is 75-(-75)? Why don't we just use 75V?
See above. What is the difference in electrostatic potential between the plates?
3) Charge stored on each plate is it the same as charge stored in the whole capacitor?
:confused:

One plate has positive charge (+Q) and the other plate has negative charge of the same magnitude (-Q). By convention, when we say "the charge on the capacitor", we mean the charge on the positive plate, +Q.
 
Thanks.
 
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