Potential Divider: R(R+r)*E=V - Wrong Ans Explained

If it is in series with the LDR, then it should also be seeing a bigger voltage drop when there is high illumination. That means it is getting more current and heating up, so its resistance will also fall. That would tend to pull the output voltage lower. What do you think?In summary, the conversation discusses how the resistance of an LDR increases in low light conditions, causing a decrease in voltage across the thermistor and a lower temperature. This leads to a discussion of which answer choice is correct, with the correct answer being either B or D. The thermistor's resistance also plays a role in affecting the output voltage, as it heats up and decreases its resistance in high illumination.
  • #1
Arun Raja
17
0

Homework Statement



http://puu.sh/dzujr/dcf208c4a5.png

Homework Equations


Potential divider concept--> R(R+r)*E=V

The Attempt at a Solution


When there is low light, resistence of LDR increase to produce light.

So, voltage across LDr increases and voltage across thermistor decrease-->lower temperature

so I think answer B , but it is wrong
 
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  • #2
This isn't really "advanced" physics (so the moderators might move it to another sub forum) but..

Arun Raja said:
When there is low light, resistence of LDR increase [strike]to produce light[/strike].

That first part is correct. More light (high illumination) causes the resistance of the LDR to fall. That will tend to "pull" the output voltage higher. That reduces your choices to B or D.

Now what about the thermistor?
 

1. What is a potential divider?

A potential divider is an electrical circuit consisting of two or more resistors connected in series that divides the input voltage into smaller output voltages. It is commonly used to control the output voltage of a circuit by adjusting the values of the resistors.

2. How does a potential divider work?

A potential divider works by using the ratio of the resistances in the circuit to divide the input voltage. The output voltage is determined by the ratio of the resistance values, with a higher resistance resulting in a smaller output voltage and vice versa.

3. What is the formula for calculating the output voltage in a potential divider?

The formula for calculating the output voltage in a potential divider is Vout = (R2 / (R1 + R2)) * Vin, where R1 and R2 are the resistances in the circuit and Vin is the input voltage. This assumes that the output is taken from the junction between the two resistors.

4. Why is the formula R(R+r)*E=V often wrong?

The formula R(R+r)*E=V is often wrong because it is a simplified version of the actual potential divider formula and only works in certain cases. It assumes that the output voltage is taken from the junction between the two resistors, but if the output is taken from a different point in the circuit, this formula will not give the correct result.

5. How can I ensure I am using the correct formula for a potential divider?

To ensure that you are using the correct formula for a potential divider, it is important to understand the concept and principles behind it. The most accurate formula is Vout = (R2 / (R1 + R2)) * Vin, but it is also important to consider the placement of the output and any other factors that may affect the circuit. It is always best to double check your calculations and consult a reliable source if you are unsure.

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