How far along the incline is the highest point from the release point?

AI Thread Summary
A block with a mass of 2.00 kg is placed against a spring on a frictionless incline at a 30.0° angle, with the spring compressed by 20.0 cm before release. The spring constant is 19.6 N/cm, equating to 1960 N/m. To determine how far along the incline the block travels after release, the principle of conservation of energy is applied, equating the potential energy stored in the spring to the gravitational potential energy at the block's highest point. The calculations involve using the spring force and gravitational potential energy formulas, with attention to trigonometric components due to the incline. The solution requires careful consideration of energy transformations and angles.
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Homework Statement


A block with mass m=2.00kg is placed against a spring on a frictionless incline with angle θ=30.0°. The spring, with spring constant k=19.6N/cm, is compressed 20.0cm and then released.

Homework Equations


How far along the incline is the highest point from the release point?

The Attempt at a Solution


k=19.6N/cm=1960N/m k=spring coefficient
x=20cm=.20m x=distance spring was compressed
WK=work
F=force
d=distance
Fspring= -kx= -(1960N/m)(.20m)= -392N

392N=Fspring WK=F×d
 
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helpmeimdumb said:

Homework Statement


A block with mass m=2.00kg is placed against a spring on a frictionless incline with angle θ=30.0°. The spring, with spring constant k=19.6N/cm, is compressed 20.0cm and then released.


Homework Equations


How far along the incline is the highest point from the release point?

Do you know the formula for the potential energy of a spring? Do you know the formula for gravitational potential energy? Basically to solve this problem you have to write and solve equation that says "energy before equals energy after". And for both "before" (when the spring is fully compressed) and after (when the mass is at its maximum height), the kinetic energy is zero. The hardest part is doing the trig.

BBB
 
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