Potential Energy and Kinetic Energy

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SUMMARY

The discussion focuses on the calculation of gravitational potential energy and kinetic energy in a system involving two blocks of different masses (1.5 kg and 3.0 kg) connected by a pulley. The change in gravitational potential energy when the 3.0 kg block drops 0.60 m is calculated as -8.82 J, accounting for both blocks' movements. The kinetic energy at this instant is determined to be 8.82 J, indicating that the potential energy lost is converted into kinetic energy. The velocity of the 1.5 kg block is derived using the kinetic energy formula, resulting in a value of 4.85 m/s.

PREREQUISITES
  • Understanding of gravitational potential energy (U = m*g*h)
  • Knowledge of kinetic energy formula (K = 1/2 m*v^2)
  • Basic principles of mechanics involving pulleys and mass
  • Ability to solve equations with multiple variables
NEXT STEPS
  • Study the relationship between potential energy and kinetic energy in mechanical systems
  • Explore the concept of conservation of energy in physics
  • Learn about the dynamics of pulley systems and their applications
  • Investigate the effects of mass and height on gravitational potential energy calculations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of energy conversion in systems involving pulleys and multiple masses.

Manh
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Homework Statement


Two blocks are hung by a string draped over a pulley, a 1.5-kg block on the left and a 3.0-kg block on the right. The two blocks start out at rest and at the same height.

A. What is the change in the gravitational potential energy of the system of blocks and Earth when the 3.0-kg block has dropped 0.60 m ?
B. What is the change in the kinetic energy of the system between release and this instant?
C. What is the velocity of the 1.5-kg block at this instant?

Homework Equations


U = m*g*h
K = 1/2 m*v^2

The Attempt at a Solution


A. U = (3.0 kg)(9.8 m/s^2)(0.60)
= 17.64 J
I wonder if the answer should have a negative sign!

B. K = 17.64 J
Since U is converted to K, therefore K has the same value of U. Am I correct?

C. 17.64 = 1/2*(1.5)*v^2
v = 4.85 m/s
These are my works and answers. I hope somebody can help me check them. Thanks!
 
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Manh said:
A. U = (3.0 kg)(9.8 m/s^2)(0.60)
= 17.64 J
I wonder if the answer should have a negative sign!
Don't ignore the movement of the 1.5 kg mass. (As far as sign, when something lowers the change in gravitational PE is negative.)

Manh said:
B. K = 17.64 J
Since U is converted to K, therefore K has the same value of U. Am I correct?
Yes, but you have the wrong value. (See A.)

Manh said:
C. 17.64 = 1/2*(1.5)*v^2
v = 4.85 m/s
These are my works and answers. I hope somebody can help me check them. Thanks!
Realize that the total kinetic energy is for both masses.
 
Doc Al said:
Don't ignore the movement of the 1.5 kg mass. (As far as sign, when something lowers the change in gravitational PE is negative.)
A. U1 = (1.5 kg)(9.8 m/s^2)(0.6 m) = 8.82 J
U2 = (3 kg)(9.8 m/s^2)(-0.6 m) = -17.64 J
delta U = -17.64 J + 8.82 J = -8.82 J
Doc Al said:
Yes, but you have the wrong value. (See A.)
B. delta K = 8.82 J
Doc Al said:
Realize that the total kinetic energy is for both masses.
C. K = 1/2 m1*v1^2 + 1/2 m2*v2^2. Where K = 8.82 J. Is this correct?
 
Manh said:
C. K = 1/2 m1*v1^2 + 1/2 m2*v2^2. Where K = 8.82 J. Is this correct?
Yes, but what is the relationship between the two velocities?
 
wouldn't you end up with 2 variables v1 and v2?
 

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