Potential energy in 2 gravity fields

AI Thread Summary
Potential energy due to gravity is calculated using the formula m * g * h, where g varies between celestial bodies. When lifting a weight on the Moon, the potential energy is 1.6 * m * h, while on Earth it is 9.8 * m * h. The added energy when transitioning from the Moon to Earth does not come from the travel itself, as the gravitational fields differ significantly. The gravitational field is not homogeneous at large scales, complicating direct comparisons of potential energy. Understanding these differences is crucial for accurately discussing potential energy in varying gravitational fields.
flm
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Hi everyone,

First, sorry if the question is stupid, I do not have any background
in Physics. Just very curious.

Potential energy due to gravity is:
m * g * h Joules

Now, suppose I lift a weight on Moon at a given height. I will have:
1.6 * m * h Joules

I maintain it at that height and go to Earth. There, I will have:
9.8 * m * h Joules

Where does the added energy come from ? I cannot see why it would
come from the Moon Earth travel itself, as only the mass matters during
the motion ...

Thanks for your time and answers !

Cheers,

Fabien.
 
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First of all, the mgh formula is only a valid approximation as long as the gravitational field may be considered homogeneous. At scales as large as the distance from the gravitational center, this is no longer true.

flm said:
I maintain it at that height and go to Earth.
You cannot do this. In order to transport it to Earth, it needs to change its height from both the lunar surface and the Earth's surface. This involves a change under which the gravitational field most certainly is not homogeneous. In addition, the zero-point of the different potentials are chosen differently. You are comparing apples and carrots.
 
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