Potential energy of a force vector

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To find the potential energy from a conservative force vector F = kx i + ky j + kz k, one must derive a scalar function V(x,y,z) that satisfies the conditions dV/dx = Fx, dV/dy = Fy, and dV/dz = Fz. This involves integrating the components of the force to obtain Ux, Uy, and Uz, resulting in U(x, y, z) = (1/2)k(x^2 + y^2 + z^2) + C, where C is a constant determined by boundary conditions. The integration path can be segmented for easier evaluation of the integral U = -∫ F · ds. The constant C can be set to zero at a convenient reference point since initial conditions are not provided. The final expression for potential energy is confirmed to be correct as long as the partial derivatives yield the force components.
element1945
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If F is a conservative force, written in terms of a vector:

F = kx i + ky j + kz k where k is a constant,

How do i find the potential energy?

I know how to use partial derivatives, but I am not sure how to integrate a vector. Please Help.
 
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I think you have somewhat the wrong perspective on this.

By definition, the potential is a scalar function V(x,y,z) such that
dV/dx = Fx
dV/dy = Fy
dV/dz = Fz
where those are all partial derivatives, not ordinary derivatives.
Finding V(x,y,z) is a matter of solving this system of partial differential equations, that is finding a function that has the correct partial derivatives.
 
so i just integrate the components;

Ux = k/2 x^2

Uy = k/2 y^2

Uz = k/2 z^2

how do i put U as a scalar function?
 
element1945 said:
How do i find the potential energy?

1. Choose the point {\vec r}_0 = x_0 \hat i + y_0 \hat j + z_0 \hat j at which you want the potential energy to be zero.

2. Choose a path between {\vec r}_0 and \vec r = x \hat i + y \hat j + z \hat j that makes it easy to evaluate the integral

U = - \int^{\vec r}_{{\vec r}_0}{\vec F \cdot d \vec s}

where d \vec s = dx \hat i + dy \hat j + dz \hat k. The force is conservative, so you should get the same result no matter which path you choose. There are no wrong paths, only easier and harder ones. :wink:

Hint: Often it's best to break up the path into segments, each of which is individually easy to do, rather than use a single "straight-line" path that gives you a messier integral.

3. Evaluate the product \vec F \cdot d \vec s and perform the integral. If you chose a path in segments, you'll probably have to do this step separately for each segment. Then, of course, you find the sum for all the segments.
 
Thanks a lot, but something that i don't understand is how to choose the segments of the path... can i just evaluate the indefinite integral?
 
When you integrated the first part, you should have written
U = (1/2)*k*x^2 + f(y,z)
From the second,
U = (1/2)*k*y^2+g(x,z)
and from the third,
U = (1/2)*k*z^2 + h(x,y)
Then you ask yourself how to satisfy all of these and see what will do the job.
 
yeah i forgot the constants...but i thought i wouldn't need them...because i don't have initial conditions to solve for them. thanks
 
ohhhhhhhh i just need to derive these equations and substitute the constants and find U (x, y, z) Thank you so much guys!
 
U (x , y , z) = (1/2)*k*x^2 + (1/2)*k*y^2 + (1/2)*k*z^2 + C I am i correct?
 
  • #10
Well, you answer the question. Do the partial derivatives give the force components?

As you observed, you don't have the conditions to evaluate C, so you can make it zero anywhere that is convenient (and meaningful) for the problem.
 
  • #11
Thank you very much.
 
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