How Do Two Point Charges Affect Potential Above a Grounded Conducting Plane?

AI Thread Summary
The discussion focuses on calculating the electric potential V(x,y,z) above a grounded conducting plane due to two point charges, q1 and q2. The potential is determined using the principle of superposition, where the total potential at any point is the sum of the potentials from the two real charges and their corresponding image charges. The potential formula for a single point charge is applied, and the user confirms that the potential at z=0 must equal zero to satisfy the grounded condition. The approach involves using Cartesian coordinates to express the distances from the charges to the point of interest. The solution emphasizes the necessity of incorporating both charges and their images to accurately describe the potential above the conductor.
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Homework Statement



Two point charges q1 and q2 are located on a straight line normal to a grounded (V=0) conducting plane. Choosing the z axis to go through the charges, q1 is at a distance z1 above the conductor, and q2 is at a distance z2.

Find the potential V(x,y,z) everywhere above the conductor.


Homework Equations





The Attempt at a Solution



I know the formula for the potential of 1 point charge in open space. I can also use image charges to define the potential at a point V(x,y,z > 0). But for two charges, would the potential at any point be the sum of the individual potentials?
 
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Yes, the potential at a point (x,y,z > 0) is the sum of the potentials due to the two real and two virtual charges. Otherwise how would you ever get the potential to be zero at z=0?
 
So as of now, my answer is

q1/(4pi e0) * 1/r [from (z-d) to (z+d)]

and in cartesian coordinates, r is (x^2 + y^2 + z^2)^1/2

and i would just sum this up with the same process except for q2?
 
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