Potential Step where E>V0. λ(II) always twice λ?

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SUMMARY

The discussion centers on the behavior of a particle encountering a potential step where the energy (E) exceeds the potential height (V0). It is established that the characteristic wavelength (λ) in region II is consistently twice that of region I, denoted as λ(II) = 2λ(I). This relationship holds true under the condition that E >> V0, leading to negligible differences in wavefunction behavior across the step. The participant references the Schrödinger equation solutions for further clarification on this phenomenon.

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Homework Statement



I have been attempting some questions on a particle approaching a potential step where

E>V0

I have the provided solutions for all the questions and I noticed that λ(II) is always twice the value of λ in all the questions.

Is there some inherent reason for this, and is it always the case with this type of problem?

Thank you.


Homework Equations





The Attempt at a Solution

 
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What type of problem?

Assuming I and II are the regions before and after the step respectively, and λ is a characteristic wavelength of the wavefunction, so that k=2π/λ

If E >> V, the height of the step, then there should be almost no difference.
If E ~ V, then there should be some reflection off the edge of the step.

http://en.wikipedia.org/wiki/Soluti...nergy_greater_than_step_height_.28E_.3E_V0.29

Perhaps the problem was set up numerically so that E=(4/3)V or something?
 

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