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Potential Step where E>V0. λ(II) always twice λ?

  1. Nov 21, 2012 #1
    1. The problem statement, all variables and given/known data

    I have been attempting some questions on a particle approaching a potential step where

    E>V0

    I have the provided solutions for all the questions and I noticed that λ(II) is always twice the value of λ in all the questions.

    Is there some inherent reason for this, and is it always the case with this type of problem?

    Thank you.


    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Nov 22, 2012 #2

    Simon Bridge

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    What type of problem?

    Assuming I and II are the regions before and after the step respectively, and λ is a characteristic wavelength of the wavefunction, so that k=2π/λ

    If E >> V, the height of the step, then there should be almost no difference.
    If E ~ V, then there should be some reflection off the edge of the step.

    http://en.wikipedia.org/wiki/Soluti...nergy_greater_than_step_height_.28E_.3E_V0.29

    Perhaps the problem was set up numerically so that E=(4/3)V or something?
     
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