a charged capacitor has capacitance C and charge Q. a resistor R is then connected what is the power dissipated right after the connection?(adsbygoogle = window.adsbygoogle || []).push({});

V=Q/C

so P=V^2/R=Q^2/(RC^2)

is this right?

what is the power dissipated in the resistor when the energy stored in the capacitor has decreased to half the initial value?

Using P=V^2/R, we need to find V when U=1/2U_o

This means, U=(1/4)Q^2/C

I'm not actually sure of how to get the voltage, to get the power dissipated. any ideas?

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# Homework Help: Power dissipated in capacitor

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