a charged capacitor has capacitance C and charge Q. a resistor R is then connected what is the power dissipated right after the connection? V=Q/C so P=V^2/R=Q^2/(RC^2) is this right? what is the power dissipated in the resistor when the energy stored in the capacitor has decreased to half the initial value? Using P=V^2/R, we need to find V when U=1/2U_o This means, U=(1/4)Q^2/C I'm not actually sure of how to get the voltage, to get the power dissipated. any ideas?