Power - Ferris Wheel with friction

AI Thread Summary
The discussion revolves around calculating the power of a motor that maintains a Ferris wheel's rotation against friction. The wheel has a moment of inertia of 8.95 x 10^7 kg·m² and slows from 6.3 rev/hr to 3.5 rev/hr in 25 seconds after the motor is turned off. Participants suggest converting the rotational speeds from revolutions per hour to radians per second to facilitate calculations. The formula for power, P = ΔW/Δt, is referenced, indicating the need to determine work done against friction. The conversation also includes a light-hearted exchange about being in the same class.
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Homework Statement


A motor keep a Ferris wheel (with moment of inertia 8.95X10^7 kg X m^2)rotating at 6.3 rev/hr. When the motor is turned off, the wheel slow down (because of friction) to 3.5 rev/hr in 25 s. What was the power of the motor that kept the wheel rotating at 6.3 rev/hr despite friction? Answer in units of W.

Homework Equations


P = \DeltaW/\Deltat

The Attempt at a Solution


Well, if I interpret it correctly, I guess I have to convert 3.5 rev/hr to rad/s. Correct? And find W by FD? Sorry, I am too sure what to do. Thanks for your help.
 
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SORRY, someone else posted it already
 
You wouldn't by chance be in Professor Woods' class?
 
Bearbull24.5 said:
You wouldn't by chance be in Professor Woods' class?

I am in his class. I can tell you are since you have "Bull" in your username. ;)
 

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