Power Hydraulics: Calculate Cylinder Diameter

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To calculate the cylinder diameter in a hydraulic circuit with a pressure of 72 bar, the inner rod diameter of 15 mm is given. The retract speed is stated to be four times faster than the extend speed, which suggests a relationship between the areas of the inner and outer circles. The area of the outer circle can be determined by knowing that it is four times greater than the area of the inner circle plus the area difference. The pressure is deemed irrelevant for this calculation, and the formula Q=V x A can be utilized to find the necessary area. This approach should lead to the correct diameter calculation.
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hello..i m phasing a problem..i have an hydraulic circuit with pressure 72 bar and i want to find the cylinder diameter. I have that rod diameter is 15 mm and the speed of the cylinder is 4 times higher than the rod..please help me because i seraching days for this solution which i m sure that is very easy but i can't find nothing.. I think that the informations i have are not enough! thnx..
 
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If you're saying retract speed is 4X faster than extend speed...

Draw a circle inside of another circle. You are looking for the area of the outer circle. from that you can calculate the diameter and have your answer.

The area of the inner circle is known (15mm dia).

The area of the outer circle is 4x greater than the (area of the outer circle minus the area of inner circle).

Pressure is irrelevant. Is there enough information?
 
Evil Bunny said:
If you're saying retract speed is 4X faster than extend speed...

Draw a circle inside of another circle. You are looking for the area of the outer circle. from that you can calculate the diameter and have your answer.

The area of the inner circle is known (15mm dia).

The area of the outer circle is 4x greater than the (area of the outer circle minus the area of inner circle).

Pressure is irrelevant. Is there enough information?

i know that Q=V x A..SO--> 4V x A=V x (A-a) and then i can find A..Is that right?
 

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