Power of a battery calculation

[electrohau5]

Homework Statement

Calculate the power Pa and Pb supplied by batteries A and B respectively

(see attached diagram)

Homework Equations

P=iV, P=i^2R, and P=V^2/R

The Attempt at a Solution

I already found i1, i2 and i3 to be 5.714, 1.143, and -4.571 respectively.

I am confused over the difference between P=iV, P=i^2R, and P=V^2/R
so I am not sure what to do next.

 

[CWatters]

You could use I^2R to work out the power dissipated in each resistor BUT that wouldn't necessarily tell you which battery supplied it or how much (at least not without further calculations).

The power delivered by a battery is simply the battery voltage multiplied by the battery current.

 

[gneill]

Homework Statement

Calculate the power Pa and Pb supplied by batteries A and B respectively

(see attached diagram)

Homework Equations

P=iV, P=i^2R, and P=V^2/R

The Attempt at a Solution

I already found i1, i2 and i3 to be 5.714, 1.143, and -4.571 respectively.

You'll have to supply component values if we're to check your work.

I am confused over the difference between P=iV, P=i^2R, and P=V^2/R
so I am not sure what to do next.

Each of the expressions will yield the same value for power if you know the current, voltage, and resistance of the given component. For components without a specified resistance (such as ideal voltage supplies or current supplies) you would choose the P = IV expression, having obtained the voltage and current for the device.

 

[barryj]

"I am confused over the difference between P=iV, P=i^2R, and P=V^2/R"
Start with P = VI and recall that V = IR
Substitute IR for V in P = VI and you get P = I^2R
From V = IR, I = V/R Substitute V/R for I and you get P = V^2/R

 

[electrohau5]

You'll have to supply component values if we're to check your work.

Each of the expressions will yield the same value for power if you know the current, voltage, and resistance of the given component. For components without a specified resistance (such as ideal voltage supplies or current supplies) you would choose the P = IV expression, having obtained the voltage and current for the device.

So would I in P=IV be I1, since it goes through each battery, and would V be the emf of each battery?

 

[gneill]

So would I in P=IV be I1, since it goes through each battery, and would V be the emf of each battery?

Right. Be careful with the current direction; current flowing out of the + terminal of the battery means the battery is supplying power to the circuit, while current flowing into the + terminal means the battery is sinking (absorbing) power.

 

[CWatters]

What gneil said. In this circuit both batteries are supplying power, however you might come across other problems involving two batteries where the direction of the current means one battery is being charged by the other. In that case the power delivered by the battery being charged is negative.

 

[electrohau5]

thanks guys, I think I got this now