Power of Niagara Falls: How Many 80 W Bulbs Can It Power?

  • Thread starter Thread starter Unknown_20
  • Start date Start date
  • Tags Tags
    Power
AI Thread Summary
The discussion focuses on calculating the power generated by the water flow at Niagara Falls, which has a mass flow rate of 1.38 x 10^6 kg/s and a drop height of 32 m. Using the formula for force (mass times acceleration) and the relationship between power, work, and time, participants explore how to determine the total power output. The calculations involve converting the work done into watts to find out how many 80 W light bulbs can be powered. The conversation emphasizes the application of Newton's second law and the principles of energy conversion. Ultimately, the discussion aims to quantify the immense energy potential of Niagara Falls in terms of electrical power generation.
Unknown_20
Messages
7
Reaction score
0
Water flows over a section of Niagara Falls at
a rate of 1.38 x 10^6 kg/s and falls 32 m.
The acceleration of gravity is 9.8 m/s2 .
How many 80 W bulbs can be lit with this
power?
 
Physics news on Phys.org
Unknown_20 said:
Water flows over a section of Niagara Falls at
a rate of 1.38 x 10^6 kg/s and falls 32 m.
The acceleration of gravity is 9.8 m/s2 .
How many 80 W bulbs can be lit with this
power?

Force = Mass*Acceleration, which in this case will be in Newtons.
P = Force*distance / time, note that force*distance is also called "work" and the units of work are "Joules". A watt is Joules over time, which is exactely what this equation comes up with.

That should be all you need to know.
 
thanks for the help.
 
If i am not mistaken, here we have to use Newton's second law in real form that's
f=d/dt(m*v)
here velocity is not the variable but the mass (check kg/s)
work done = f*d/time

you can do the rest.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top