Power of Wavefront Penetrating Dielectric Material

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Homework Help Overview

The discussion revolves around the proportion of a wavefront's power that penetrates a dielectric material's surface during a perpendicular collision from air, with a focus on the relative permittivity parameter.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the ratio of the complex Poynting vectors for the wavefronts in air and the dielectric material, leading to a conclusion that the output power is four times the input power. Some participants question the validity of this result and the assumptions made in the calculations.

Discussion Status

Participants are engaged in exploring the calculations and assumptions related to the power penetration in dielectric materials. Guidance has been offered regarding the formatting of mathematical expressions, and there is acknowledgment of the original poster's efforts.

Contextual Notes

There is a mention of potential confusion regarding the mathematical notation used, which may affect the clarity of the discussion. The original poster expresses uncertainty about the outcome of their calculations.

DemoniWaari
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Homework Statement


How large proportion of wavefront's power penetrates dielectric material's surface in a perpendicular collision from air. The only parameter that I have is \varepsilon_r = 16 where \varepsilon_r is the relative permittivity.

Homework Equations


\varepsilon = \varepsilon_r \varepsilon_0
\eta = \sqrt{\frac{\mu}{\varepsilon}} Where \mu = \mu_0 Because of the dielectric material.
\vec E(\vec r) = \vec E_0 e^{-j \vec k \cdot \vec r}
\vec H(\vec r) = \frac{1}{\eta} \vec E_{0p} e^{-j \vec k \cdot \vec r} Where \vec E_{0p} is perpendicular to \vec E_0 and has the same magnitude.
\vec S(\vec r) = \frac{1}{2} \vec E(\vec r) \times \vec H(\vec r)^{*} The complex poyinting vector.

The Attempt at a Solution



\vec E_+(\vec r) = \vec E_0 e^{-j \vec k_1 \cdot \vec r} wavefront in the air.
And
\vec E_-(\vec r) = \vec E_0 e^{-j \vec k_2 \cdot \vec r} wavefront in the material
And \eta_1 = \sqrt{\varepsilon_0 \mu_0} is the wave impedance.
Thus we get
\vec H_+(\vec r) = \frac{1}{\eta_1} \vec E_{0p} e^{-j \vec k_1 \cdot \vec r}
And
\vec H_-(\vec r) = \frac{1}{\eta_2} \vec E_{0p} e^{-j \vec k_2 \cdot \vec r}
Now the complex poyinting vectors are
\vec S_+(\vec r) = \frac{1}{2} \vec E_+(\vec r) \times \vec H_+(\vec r)^{*}
We're not interested in the directions so we can just check the magnitudes thus we get.
\vec S_+(\vec r) = \frac{1}{2\eta_1} |E_0|^2
And same thing for the other wavefront...
\vec S_-(\vec r) = \frac{1}{2\eta_2} |E_0|^2

So the passing fraction is
\frac{ \vec S_-(\vec r)}{\vec S_+(\vec r)} =<br /> \frac{\frac{1}{\eta_2}}{\frac{1}{\eta_1}} = \frac{\eta_1}{\eta_2} =<br /> \frac{\sqrt{\frac{\mu_0}{\varepsilon_0}}}<br /> {\sqrt{ \frac{\mu_0}{\varepsilon_r \varepsilon_0} }} = \sqrt{\epsilon_r}=4

So interestingly output is four times higher than input... So I have a problem here =(
 
Last edited:
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I suggest to use [itex.] rather than [tex.] or the latex will be displayed on a new line for each expression.
When you close the [itex.], use [/itex.] rather than [\itex.]. This is the reason why it doesn't work.
Without the . inside the []'s.
 
OH YES!
Thank you kind sir.
 
Penetrated power = incident power minus reflected power.
 

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