Power Rule Question: Why Did 1-2x Become 2x-1?

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I just did a problem that made use of the power rule. Here is the final step:

(1-2x)
-------------
-(x-x^2)^5/4

=

(2x-1)
-------------
-(x-x^2)^5/4


Why did 1-2x become 2x-1 (2x-1 is the answer according to my book)??
 
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Are you sure there's a minus sign in both denominators?
 
yep I'm looking at the solution manual right now...
 
Well, that can't be right. :wink: (I suspect a typo.)
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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