Practical limit on Resolution (Diffraction Grating)

AI Thread Summary
The discussion centers on the practical limits of using high orders of diffraction in diffraction gratings to enhance resolution. The resolution is calculated using the formula R = λ / Δλ = Nm, where N represents the number of grooves and m the order of diffraction. As higher orders are used, the angle of diffraction increases, which can lead to issues such as overlapping spectra and reduced intensity. The practical limit is reached when these factors compromise the clarity and usability of the resulting data. Understanding these limitations is crucial for effectively utilizing diffraction gratings in experimental setups.
bphysics
Messages
33
Reaction score
0

Homework Statement



In order to increase resolution of the diffraction gratings we can use them in higher orders of diffraction. What is the practical limit on using very high orders of diffraction?

Homework Equations



R = \lambda / \Delta\lambda = Nm

The Attempt at a Solution



I understand how to calculate the resolution via the above equation, but I'm not sure I understand where to draw the line for a practical limit
 
Physics news on Phys.org
How does order effect the angle the light comes off the grating at?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Number of bright fringes given by diffraction grating on a screen
Replies
6
Views
3K
Calculating the Number of Lines for a Diffraction Grating
Replies
3
Views
2K
What is the effect on a diffraction pattern when reducing the width of the slit?
Replies
11
Views
3K
Diffraction Grating: Possible variables for Experiment
Replies
5
Views
2K
Diffraction Grating wavelength
Replies
3
Views
2K
Diffraction grating problem involving Snell's Law
Replies
3
Views
5K
Maxima in a diffraction grating
Replies
2
Views
3K
Calculating the Number of Lines on a Diffraction Grating
Replies
8
Views
27K
I DMD optical Setup: Diffraction-limited resolution
Replies
3
Views
113
Electron Velocity Diffraction Grating Problem
Replies
4
Views
1K

Hot Threads

Recent Insights

Back
Top