Understanding Polynomial and Rational Functions: Tips and Tricks

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The degree of a polynomial is determined by the largest exponent in the polynomial. To find the exact zeros of the polynomial 32x^4-28x^3+113x^2-112x-60, the rational root theorem can be applied, where possible rational roots are factors of the constant term divided by factors of the leading coefficient. Candidates should be tested systematically, and it can be noted that if the denominator is 1, only even factors need to be checked. Finally, after identifying the roots, the polynomial can be expressed as a product of irreducible linear and quadratic factors. Understanding these concepts is essential for mastering polynomial and rational functions.
NickK
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:confused: Right now we are Studying Polynomial and Rational Functions and some things just have me puzzled. Such as

1. Is the degree of the polynomial the biggest exponent in the polynomial of x?
2. Whats the best way (or any way) to find the wxact zeros of this = 32x^4-28x^3+113x^2-112x-60?
3. How do you write the equation above as the product of linear and quadratic factors that are irreductible over the reals?


Any help would be appreciated :smile:
 
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NickK said:
1. Is the degree of the polynomial the biggest exponent in the polynomial of x?

Yes. For example, the beast you give below has degree 4.

NickK said:
2. Whats the best way (or any way) to find the wxact zeros of this = 32x^4-28x^3+113x^2-112x-60?

Hrm, that's a biggie. Start with the rational root theorem that states if p/q is a rational root of this polynomial then p is a factor of 60 and q is a factor of 32. Have you seen this before? Try all these candidates as roots until you find one. Then divide out by the corresponding linear factor and repeat the process. One thing to notice to save a bit of time is that if q=1, then if p is odd and p/q, which just equals p, is a root you'd have:

32p^4-28p^3+113p^2-112p-60=0

or

even#-even#+odd#-even#-even#=even#

Which is impossible. So if q=1, p must be even. This means you don't have to check plus or minus 1/1, 3/1, 5/1, or 15/1 as candidates for roots.


NickK said:
3. How do you write the equation above as the product of linear and quadratic factors that are irreductible over the reals?

Try the above first, and report back what you've got. So you don't despair, there are indeed rational roots for this guy.
 
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thanks a lot. I got it now :smile:
 
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