Pressure above & below the surface of a lake.

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SUMMARY

The discussion centers on calculating pressure changes in a freshwater lake. The initial pressure at the surface is 106 kPa. For a depth of 35.1 meters, the correct formula to use is P = ρgd, where ρ is the density of water (approximately 1000 kg/m³), g is the acceleration due to gravity (9.81 m/s²), and d is the depth. The pressure increase is calculated without adding atmospheric pressure when determining the increase below the surface.

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  • Understanding of fluid mechanics principles
  • Familiarity with the equation P = ρgd
  • Knowledge of atmospheric pressure and its role in fluid calculations
  • Basic understanding of density and its units
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thedark_master
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At the surface of a freshwater lake the pressure is 106 kPa. (a) What is the pressure increase in going 35.1 m below the surface? (b) What is the approximate pressure decrease in going 34 m above the surface? Air at 20°C has density of 1.2 kg/m3.

i was almost sure that i needed to use this equation: P=P(atm)+ pgd but for some reason it is saying that it is wrong
please help
 
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thedark_master said:
At the surface of a freshwater lake the pressure is 106 kPa. (a) What is the pressure increase in going 35.1 m below the surface? (b) What is the approximate pressure decrease in going 34 m above the surface? Air at 20°C has density of 1.2 kg/m3.

i was almost sure that i needed to use this equation: P=P(atm)+ pgd but for some reason it is saying that it is wrong
please help

If it is demanded the pressure increase, you don´t have to add the atmospheric pressure.
 
so you are sayng that it is P=pgd?
 
omg that is the right answer, thank you
 

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