How Can I Solve This Fluid Dynamics Homework Problem?

AI Thread Summary
The discussion focuses on solving a fluid dynamics homework problem using Bernoulli's equation. The student successfully calculated pressures at points A and B but struggled with the final answer for part b. After receiving guidance, they adjusted their calculations but remained slightly off from the expected result. Participants noted that the question's ambiguous significant figures could lead to varying answers, emphasizing the importance of precision in problem statements. Overall, the conversation highlights common challenges in applying fluid dynamics principles and the need for clarity in homework questions.
Adam Rabe
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Homework Statement


Difficult pressure at pipes question.PNG


Homework Equations


AV = AV
P + 1/2*p*v^2 + pgh = P + 1/2*p*v^2 + pgh

The Attempt at a Solution


For a.) ... divide 3 by 0.1 because of (AV = AV) = 30 ms-1. answer is right.
For b.) I am stuck on this one. I tried using the 2nd relevant equation above but i can't seem to find the answer and I am sure i need to use that one. Heres my working out.

Pressure A: P + (0.5 *1000 *3^2) = 5 *10^5... Therefore P = 495500 Pa
Pressure B: P = 495500 + (0.5 *1000 *30^2) + (1000 *10 *1) = 955500 Pa
Answer is 6.5 *10^4... (65000)

For c.) point is located at the same height and same area as A, therefore pressures are equal = 5 * 10^5 Pa. Answer is right

Any help would be greatly appreciated. Thanks in advance
Adam
 
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Adam Rabe said:
Pressure A: P + (0.5 *1000 *3^2) = 5 *10^5... Therefore P = 495500 Pa
You don't seem to understand the Bernoulli equation. P is the pressure at the given point. At A it is 5*10^5 Pa. The other terms are then added to this to get a quantity that is the same throughout the streamline.
 
haruspex said:
You don't seem to understand the Bernoulli equation. P is the pressure at the given point. At A it is 5*10^5 Pa. The other terms are then added to this to get a quantity that is the same throughout the streamline.
Hello sorry for the late reply.
i think i see where i went wrong...
Using your advice, i added the pressure change due to height and subtracted the pressure difference between the two speeds (as fluid speeds up pressure must drop)

5*10^5 + (1000 *10) - ((0.5 * 1000 * 30^2) - (0.5 * 1000 * 3^2)) = 64500

But I am still 500 Pa off from the right answer, am i on the right track?
 
Adam Rabe said:
64500
That's what I get. Looks like the answers have been rounded to 2 significant figures.
The question statement is poor. It gives values like "1m2", "5x105Pa". Standard interpretation says these are only accurate to one decimal place. If you follow that through the calculation you find that the answer is indeterminate. E.g. just change the 3m/s to 3.1m/s and you get a much smaller answer. It should quote the values as 3.00m/s etc. to justify 2 sig figs in the answer.
 
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