Pressure at the bottom of a container

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To calculate the pressure at the bottom of an open glass container with 0.10 m of oil and 0.20 m of water, the pressure from each fluid must be considered separately. The pressure from the oil is calculated using its height (0.10 m) and density (850 kg/m^3), while the pressure from the water uses its height (0.20 m) and density (1000 kg/m^3). The total pressure at the bottom is the sum of the pressures from both fluids plus the atmospheric pressure. It is important to remember that the heights of the fluids are not summed for the pressure calculation; rather, the individual pressures are added together. The final pressure at the bottom of the container will include the contribution from atmospheric pressure as well.
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Homework Statement


In an open glass container, 0.10 m of oil (rho=850 kg/m^3) floats on top of 0.20 m of water (1000 kg/m^3). What is the pressure at the bottom of the glass?

Homework Equations



(rho)(h)(g)= pressure at a depth of h

The Attempt at a Solution



The only thing I'm not sure of is: for the oil, should I consider h to be o.1 m, or the sum of both heights, making h 0.3?

edit: I also know i have to add in 1 atmosphere at the end
 
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Spirochete said:
The only thing I'm not sure of is: for the oil, should I consider h to be o.1 m, or the sum of both heights, making h 0.3?
Each fluid gets its own "height". You'll find the sum of both pressures, not heights.
 
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