Pressure at the bottom of a container

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SUMMARY

The pressure at the bottom of an open glass container filled with 0.10 m of oil (density 850 kg/m³) and 0.20 m of water (density 1000 kg/m³) is calculated using the formula P = ρgh. The total pressure at the bottom is the sum of the pressures from both fluids, which requires calculating the pressure contributions separately for the oil and water, and then adding atmospheric pressure (1 atm) to the final result. The correct depth for the oil is 0.10 m, not the combined height of both fluids.

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Homework Statement


In an open glass container, 0.10 m of oil (rho=850 kg/m^3) floats on top of 0.20 m of water (1000 kg/m^3). What is the pressure at the bottom of the glass?

Homework Equations



(rho)(h)(g)= pressure at a depth of h

The Attempt at a Solution



The only thing I'm not sure of is: for the oil, should I consider h to be o.1 m, or the sum of both heights, making h 0.3?

edit: I also know i have to add in 1 atmosphere at the end
 
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Spirochete said:
The only thing I'm not sure of is: for the oil, should I consider h to be o.1 m, or the sum of both heights, making h 0.3?
Each fluid gets its own "height". You'll find the sum of both pressures, not heights.
 

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