Probability of Helium Atom Speed >1000 m/s @ 300K

leroyjenkens
Messages
615
Reaction score
49

Homework Statement


Using classical statistics, find the probability that an atom of helium in a helium gas at temperature T = 300k will have a speed greater than 1000 m/s.

Homework Equations


I think this calls for the Maxwell speed distribution.
F(v)dv=4πCe^{\frac{-mv^{2}}{2kt}}v^{2}dv

Where k = Boltzmann's constant
T = temperature.
m = mass
C = some constant
v = velocity

The Attempt at a Solution



I tried integrating this from 1000 to infinity, to find the probability that the particle would be in that range of velocities, but that integral is apparently not possible. Is there any other way to approach this problem? The teacher doesn't expect us to do ridiculous integrals, so I'm thinking I must be making this harder than it has to be.

Thanks.
 
Physics news on Phys.org
leroyjenkens said:
I tried integrating this from 1000 to infinity, to find the probability that the particle would be in that range of velocities, but that integral is apparently not possible.
It is not impossible. You can surely find a way to reduce it to a form where you will ultimately get the error function.
 
DrClaude said:
It is not impossible. You can surely find a way to reduce it to a form where you will ultimately get the error function.

Yeah I got the error function from putting it into Wolframalpha. I assumed that meant that wolfram couldn't do it, hence the "error" part.
I can get the error function, but I have no idea what to do with it. I mentioned the error function to the teacher and he made it sound like I could get something workable besides that.

Edit: Ok, I inputted actual values for all those constants, and Wolfram actually spit out a number. It gave me 4.05x10^8. Is that the probability? I thought my teacher told me in his office that the probability would be 1. That's far from 1. The number I got doesn't sound like a probability at all.
 
Last edited:
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top