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I came across this problem in a book that I bought recently. Three dices are dropped. Find the probability that when we roll the dices:
a) In all the dices we score 5. (Not as a sum) My answer:3/18 = 1/6
b) In at least one dice we score 6 My answer : 3/18=1/6
c) The sum of the scores in the dices is smaller or equal to six My answer :
we have the combinations (1 1 1), (1 1 2), (1 1 3),(1 1 4),(2 1 2), (2 1 3), (4 1 1) so my answer is 7/18
d) The sum of the scores in the dices is bigger than the product of the scores..I don't know how to do this one
e) In none of the dices we score 5 or 6.This has to be 3/18+3/18 =6/18=1/3
f) In two dices we have the same score..I don't know how to do this one either :/
a) In all the dices we score 5. (Not as a sum) My answer:3/18 = 1/6
b) In at least one dice we score 6 My answer : 3/18=1/6
c) The sum of the scores in the dices is smaller or equal to six My answer :
we have the combinations (1 1 1), (1 1 2), (1 1 3),(1 1 4),(2 1 2), (2 1 3), (4 1 1) so my answer is 7/18
d) The sum of the scores in the dices is bigger than the product of the scores..I don't know how to do this one
e) In none of the dices we score 5 or 6.This has to be 3/18+3/18 =6/18=1/3
f) In two dices we have the same score..I don't know how to do this one either :/