Problem Calculating a limit with a square root, i'm stuck

Jordash
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Problem Calculating a limit with a square root, I'm stuck :(

Homework Statement




The limit is equation 9-t / 3-sqrt(t) as t approaches 9

I'm stuck on the how to simplify this?

Thanks for any help.


Homework Equations





The Attempt at a Solution

 
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Try multiplying by (3+√t)/(3+√t)
 


I discovered that that is the conjugate and I came out with this:

27-6sqrt(t)-tsqrt(t)
----------------
9-t

So in other words, that limit does not exist. Is that right?
 


The limit does exist. Instead of multiplying by the conjugate over itself, just factor the numerator, treating it as the difference of two squares.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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