What is the Magnitude of the Acceleration in This Newton's Laws Problem?

AI Thread Summary
The discussion revolves around calculating the magnitude of acceleration for a mass subjected to three forces in an xy plane. The user initially calculated the acceleration as 0.422 m/s² but was informed it was incorrect. They computed the x and y components of the forces and divided by mass, mistakenly thinking they needed to convert mass to Newtons. The error was clarified, emphasizing that mass should remain in kilograms, and the correct acceleration was obtained after using the mass directly. The conversation highlights the importance of understanding the distinction between mass and force in physics calculations.
ednof690
Messages
2
Reaction score
0
Problem: Three forces in an xy plane act on 3.10 kg mass. 16.90 N directed at 46 deg, 7.20 N directed at 119 deg and 9.20 N directed at 218 deg . (all angles are measured from the positive x-axis, with positive angles in the counter-clockwise direction.) Calculate the magnitude of the acceleration.

F1=16.90 cos 46 x+ 16.90 sin 46 y
F2= 7.20 cos 119 x +7.20 sin 119 y
f3= 9.20 cos 218 x + 9.20 sin 218 y


I keep getting the answer .422 m/s^2, however i am told this is incorrect. I calculated the x and y components for the forces, then added them independently and then I divided each by the mass (after converting to Newtons) which should give me the acceleration. I then calculated the magnitude by using the pythag. theorem. is there a step i am missing or am i completely off?
 
Physics news on Phys.org
ednof690 said:
F1=16.90 cos 46 x+ 16.90 sin 46 y
F2= 7.20 cos 119 x +7.20 sin 119 y
f3= 9.20 cos 218 x + 9.20 sin 218 y
This seems OK. What did you get for the total force?


I keep getting the answer .422 m/s^2, however i am told this is incorrect. I calculated the x and y components for the forces, then added them independently and then I divided each by the mass (after converting to Newtons) which should give me the acceleration.
What do you mean "after converting to Newtons"? The mass should be in kg, as given. Perhaps here is your error.
 
I have no idea why i converted to Newtons, once i calculated it using the mass in kg , I got the correct accleration. In what situation would i have to convert kg to Newtons?
 
Since kg is a unit of mass, not force, you can't "convert" one to the other. Sometimes you may be asked to find the weight of a given mass, but that's gotten by w = mg.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top