Problem on distribution of charges between charged/uncharged spheres

AI Thread Summary
Two spherical conductors, B and C, initially carrying equal charges repel each other with force F. When an uncharged conductor A contacts B, charges redistribute, leaving B with Q/2 and A with Q/2. Next, A contacts C, leading to an equal distribution of the total charge (3Q/2) between A and C. Consequently, after both contacts, B retains Q/2, while A and C each have 3Q/4. The new force of repulsion between B and C is calculated to be 3F/8.
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Homework Statement



2 Spherical conductors B and C having equal radii and carrying equal charges repel each other with force F. Another conductor A having same radius as B but uncharged is brought into contact with B, and then C and then removed from both.

Find the new force of repulsion between B and C. (Answer should be 3F/8)


Homework Equations



Coulomb's law


The Attempt at a Solution



Since when an uncharged sphere A contacts with B, the charges from B flow over, leaving B with half of the charges, and A with half of the charges (initial assumption).

Afterwards charged A contacts C, but i am not quite sure about the distribution of charges from here on. Since now A have half of the original charges, does it mean that 1/4 of the charges of C will flow into A to equalise?

Or is my initial assumption that A will get half of the charges from B wrong in the first place?

Any help is much appreciated.
 
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I think the charge is going to equalise. So you can just add the charge of A and C and divide it by 2 to get the total charge on each one.

So, let's say A has 0 and B and C have Q.
A touches B so they both have Q/2.
A touches C. The charge distributes equally. So, total charge is 3Q/2. So, there will be 3Q/4 on each one.
So, you're right.
 
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