Problem: Plastic Covering One Slit in Double Slit Experiment

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Homework Help Overview

The problem involves a double-slit experiment where a thin sheet of plastic covers one slit, affecting the interference pattern observed on a screen. The focus is on determining the minimum thickness of the plastic that results in a dark center point instead of a maximum, using the principles of constructive and destructive interference.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between phase shifts and the thickness of the plastic, questioning how the equation relating thickness to phase shift was derived. There is an exploration of the meaning of the variable N and its significance in the context of phase shifts.

Discussion Status

Some participants have offered insights into the relationship between the phase shift and the path lengths of light traveling through different media. There is ongoing clarification regarding the expression of phase shifts in terms of wavelengths and how this relates to the thickness of the plastic.

Contextual Notes

Participants are navigating the complexities of phase shifts in light as it travels through different materials, with some uncertainty about the definitions and relationships involved in the equations presented.

chipwhisperer
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Homework Statement



A very thin sheet of plastic (n = 1.45) covers one slit of a double-slit apparatus illuminated by 570 nm light. The center point on the screen, instead of being a maximum, is dark. What is the (minimum) thickness of the plastic?

Homework Equations



Constructive Interference:
d *sin(theta)=m*lamda

Destructive Interference:
d *sin(theta)=(m+1/2)*lamda

lamda_n=lamda/n

The Attempt at a Solution



So I'm a TA for a physics class and I'm a little stumped on explaining this problem. The solutions manual says that the phase shift must be an odd multiple of one half. I got that. However, it then proceeds to write down this equation:

N= t/lamda_n - t/lamda = 1/2

where t is the thickness of the plastic. Any idea how they got this relation? I would really appreciate an explanation.

Thanks!
 
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t = N lambda right.
What does N represent?

number of what??
 
N equals the phase shift I believe, i.e. 1/2, I'm not exactly sure though
 
chipwhisperer said:
So I'm a TA for a physics class and I'm a little stumped on explaining this problem. The solutions manual says that the phase shift must be an odd multiple of one half. I got that. However, it then proceeds to write down this equation:

N= t/lamda_n - t/lamda = 1/2

where t is the thickness of the plastic. Any idea how they got this relation? I would really appreciate an explanation.
Well, that expression is the phase difference between the two beams that converge at the center, expressed in terms of wavelengths. (lambda is the wavelength of light in air (or vacuum), where n = 1; lambda_n is the wavelength of light in the plastic, which is lambda/n.) The physical path lengths are the same; the only difference is that one passes through a thickness of plastic (phase shift = t/lamda_n) while the other beam passes through the same thickness of air (phase shift = t/lambda).
 
Okay, I get that. But, why is the phase shift = t/lamda? I just don't see that direct correspondence.
 
chipwhisperer said:
But, why is the phase shift = t/lamda?
If a lightwave travels from points A to B, do you not agree that the phase of the light at B differs from the phase it had at A? And that the phase shift in moving from A to B can be expressed by the number of wavelengths contained in the distance between A and B? For example, if the distance A-to-B is 1/2 lambda, when the light reaches B it is exactly 180 degrees out of phase compared to its phase when at A?

Let me know if this makes sense so far.
 

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