Problem regarding concave mirror

AI Thread Summary
The discussion revolves around calculating the amplitude of the image formed by a concave mirror when a point object oscillates along the principal axis. The mirror formula is applied, with the object distance set at -15 cm and the focal length at -10 cm, leading to a derived image distance of -30 cm. Participants debate whether the motion is simple harmonic or another type, emphasizing the importance of determining the maximum and minimum object distances during oscillation. A hint provided by a user helps clarify the approach, leading to the conclusion that the amplitude of the image is 8 mm. The conversation highlights the need for a focused study approach for those preparing for competitive exams.
sankalpmittal
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Homework Statement



A point object at 15 cm from a concave mirror of radius of curvature 20 cm is made to oscillate along principal axis with amplitude 2 mm. Find the amplitude of its image.

Homework Equations



Mirror formula :

1/v + 1/u = 1/f

Here u=-15 cm , f=-10

Differentiating above formula

dv/dt = -m2 du/dt

Where m= transverse magnification=-v/u

The Attempt at a Solution



Ok I don't know if it's SHM or just another sort of oscillatory motion. Had it been SHM I would have solved it by putting maximum velocity = amplitude times angular frequency.

SHM: Simple harmonic motion.

My attempt :

1/v + 1/u = 1/f
u=-15 cm , f=-10
v=-30

Thus m=-v/u = -2

Thus

dv/dt = -4 du/dt

Now ?

Please help !

Thanks in advance...

:smile:
 
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Tedius solution method (ignore unless totally stuck):
[STRIKE]What is the range of (i.e. maximum and minimum) object distances for the object, as it is oscillating? That should help get you started.[/STRIKE]

Quicker solution method:
sankalpmittal said:
dv/dt = -4 du/dt
So what would dv/du be?
 
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Redbelly98 said:
Quicker solution method:
Maybe quick (I doubt that), but certainly wrong, this would be an approximation for small amplitudes. The amplitude is not large, but there is no reason to use an approximation here.

What is the range of (i.e. maximum and minimum) object distances for the object, as it is oscillating? That should help get you started.
That's the right approach.

You don't need velocities, or details of the motion. Just the maximal and minimal distance.
 
mfb said:
Maybe quick (I doubt that), but certainly wrong, this would be an approximation for small amplitudes. The amplitude is not large, but there is no reason to use an approximation here.

That's the right approach.

You don't need velocities, or details of the motion. Just the maximal and minimal distance.


Thanks a lot mfb and Radbelly. I got the answer.

However here Radbelly's hint had worked.
 
Hello sankalpmittal

Is 8mm the correct answer ?
 
Vibhor said:
Hello sankalpmittal

Is 8mm the correct answer ?
Please show your work.
 
Vibhor said:
Hello sankalpmittal

Is 8mm the correct answer ?


Yup. Well if you are jee aspirant I will advise you not to study from scattered sources.
 
Thanks
 
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