Problem simplifying a power function derivation

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Homework Help Overview

The discussion revolves around finding the derivative of the power function f(x) = (2x)^{\sqrt{2}} and understanding the simplification process from one expression to another. Participants are examining the steps involved in deriving and simplifying the function.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to clarify the transition from a derived expression to its simplified form, questioning the steps taken in the simplification process. Other participants engage by addressing potential misunderstandings related to the notation used in the problem.

Discussion Status

The discussion is ongoing, with the original poster seeking clarification on the simplification step. Some participants are focused on the clarity of the original poster's notation, indicating a mix of technical inquiry and communication issues.

Contextual Notes

There appears to be some confusion regarding the notation used in the problem, which may be affecting the clarity of the discussion. The original poster has expressed uncertainty about the simplification process, while others are addressing communication aspects rather than the mathematical content directly.

(glass/2)=?
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Hello All,

I can compute the solution, but I fail to see how it further simplifies into the final expression. The solution manual lists both the answer and its simplified formulation.

How do I go from step three to step four?

Homework Statement



Find the derivative of: f(x) = [itex](2x)^{\sqrt{2}}[/itex]

Homework Equations



[itex]\frac{d}{dx}[/itex]x[itex]^{r}[/itex]=r[itex]^{r-1}[/itex]

The Attempt at a Solution



1) f(x) = [itex](2x)^{\sqrt{2}}[/itex] = ([itex]2^{\sqrt{2}}[/itex])([itex]x^{\sqrt{2}}[/itex])

2) Application of the product rule: g'(x)f(x) + f'(x)g(x)

3) Answer = [itex]2^{\sqrt{2}}[/itex][itex]\sqrt{2}[/itex][itex]x^{\sqrt{2}-1}[/itex]

4) Simplification: [itex]2\sqrt{2}[/itex][itex](2x)^{\sqrt{2}-1}[/itex]

Many Thanks!
 
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Hello if you want us to see your writing you have type[tex]then type in {/tex} but with brackets[/tex]
 
mtayab1994 said:
Hello if you want us to see your writing you have type[tex]then type in {/tex} but with brackets[/tex]
[tex] <br /> mtayab1994, I don't exactly follow. Do you not see what I've posted? What do you mean by, "your writing"?<br /> <br /> Thanks[/tex]
 
(glass/2)=? said:
mtayab1994, I don't exactly follow. Do you not see what I've posted? What do you mean by, "your writing"?
I don't know what mtayab1994 was going on about - what you wrote looked perfectly clear to me.
 

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