Problem with hyperbolic functions demostrations

Rono
Messages
54
Reaction score
0

Homework Statement


Prove that cosh (\frac{x}{2}) = \sqrt{\frac{cosh(x)+1}{2}}


Homework Equations


cosh(x) = \frac{e^{x}+e^{-x}}{2}



The Attempt at a Solution


\frac{\sqrt{e^{x}}+\sqrt{e^{-x}}}{2} \ast \frac{\sqrt{e^{x}}-\sqrt{e^{-x}}}{\sqrt{e^{x}}-\sqrt{e^{-x}}} \rightarrow \frac{e^{x}+e^{-x}}{2} \ast \frac{1}{\sqrt{e^{x}}-\sqrt{e^{-x}}} \rightarrow cosh(x) \ast \frac{1}{\sqrt{e^{x}}-\sqrt{e^{-x}}}

After that, I don't know what to do. Would be glad if somebody would tell me what I'm doing wrong or how to do it. Thanks.
 
Physics news on Phys.org
<br /> cosh^2\frac{x}{2}=\frac{e^x+e^{-x}+2}{4}=\frac{cosh(x)+1}{2}<br />
That's it!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top