Problem with Improper Integration - Is Zero the Correct Answer?

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Hi again,

I have a problem regarding improper integration.

Homework Statement

feafea.JPG


Refer to the image. I tried to solve and got zero for the answer. Is that correct? I refer to my actual problem it seem like it don't won't this way...

Thanks
 
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suppose that g(t)=1, what is the value of the integral?
 
benorin said:
suppose that g(t)=1, what is the value of the integral?

If 1 is integrated, we get t and then sub in the boundary value the answer still 0?

here the actual g(t) suppose to be g(t) = cos(2\pif0t) - jsin(2\pif0t).
 
Last edited:
killerfish said:
If 1 is integrated, we get t and then sub in the boundary value the answer still 0?
Are you saying that you are not capable of integrating
\int_{-T/2}^{T/2} dt
or you just haven't bothered to?

here the actual g(t) suppose to be g(t) = cos(2\pif0t) - jsin(2\pif0t).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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