Problem with Improper Integration - Is Zero the Correct Answer?

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Homework Help Overview

The discussion revolves around improper integration, specifically questioning the correctness of an answer that evaluates to zero. Participants are examining the integral of a function, with particular attention to the implications of the function's definition.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to verify their solution of zero for an improper integral and expresses uncertainty about the correctness. Some participants question the integration process and the implications of the function g(t) being equal to 1, while others reference the actual form of g(t) as a complex function involving cosine and sine.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the integral and questioning the integration steps. There is no explicit consensus on the correctness of the original poster's answer, and multiple perspectives on the function g(t) are being considered.

Contextual Notes

Participants are discussing the boundaries of the integral and the nature of the function g(t), which may affect the evaluation of the integral. There is mention of potential confusion regarding the integration limits and the behavior of the function involved.

killerfish
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Hi again,

I have a problem regarding improper integration.

Homework Statement

feafea.JPG


Refer to the image. I tried to solve and got zero for the answer. Is that correct? I refer to my actual problem it seem like it don't won't this way...

Thanks
 
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suppose that g(t)=1, what is the value of the integral?
 
benorin said:
suppose that g(t)=1, what is the value of the integral?

If 1 is integrated, we get t and then sub in the boundary value the answer still 0?

here the actual g(t) suppose to be g(t) = cos(2\pif0t) - jsin(2\pif0t).
 
Last edited:
killerfish said:
If 1 is integrated, we get t and then sub in the boundary value the answer still 0?
Are you saying that you are not capable of integrating
\int_{-T/2}^{T/2} dt
or you just haven't bothered to?

here the actual g(t) suppose to be g(t) = cos(2\pif0t) - jsin(2\pif0t).
 

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