Problem with Newton's second law

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Homework Help Overview

The discussion revolves around a physics problem involving Newton's second law, specifically focusing on a scenario with a boy and a platform. The problem requires finding the acceleration of the boy and the reading of a scale, given specific forces and masses.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to set up equations based on forces acting on the boy and the platform, questioning the relationship between tension and the scale reading. They express uncertainty about how to incorporate a given force of 180N into their calculations.

Discussion Status

Some participants confirm the correctness of the original poster's approach and suggest methods for solving the simultaneous equations presented. There is an indication of agreement among participants regarding the validity of the setup, although no explicit consensus is reached.

Contextual Notes

The problem includes specific masses and forces, but there may be assumptions regarding the system's setup that are not fully explored. The original poster's uncertainty about the 180N force suggests potential gaps in understanding the problem context.

Bohrok
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Homework Statement



In the following figure, the boy has a mass of 40kg, and the platform he is sitting on has a mass of 15kg. If the force of the board on the boy is 180N;

a) Find the acceleration of the boy

b) Find the reading of the scale.

http://www.csupomona.edu/~jarmand/131/131chall5s12_files/image002.gif

Homework Equations



F = ma

The Attempt at a Solution



I think I have the acceleration kind of worked out with ƩFy = 2T - mg = may where m is the total mass of the system (platform + boy) and T is the tension in the rope. Would the force of the tension be the same as the reading on the scale?

Mostly I've been unsure how to use that 180N. Then I started thinking that the downward force that the boy exerts on the chair has the same magnitude as the upward normal force that the chair exerts on the boy, giving ƩFy = T + Fn - mboyg = mboyay
Two equations with two unknowns T and a:
2T -55(9.8) = 55a
T + 180 - 40(9.8) = 40a
?
 
Last edited by a moderator:
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That all looks correct. Do you not know how to solve simultaneous equations? Just get one of the equations in the form T = (some function of other variables) and use this to substitute for T in the other equation.
 
Oh I know how to solve simultaneous equations; I just wanted to see if my work seemed alright :smile:
Thanks!

If no one else chimes in, I'll take it that they agree
 
Bohrok said:

Homework Statement



In the following figure, the boy has a mass of 40kg, and the platform he is sitting on has a mass of 15kg. If the force of the board on the boy is 180N;

a) Find the acceleration of the boy

b) Find the reading of the scale.

[ IMG]http://www.csupomona.edu/~jarmand/131/131chall5s12_files/image002.gif

Homework Equations



F = ma

The Attempt at a Solution



I think I have the acceleration kind of worked out with ƩFy = 2T - mg = may where m is the total mass of the system (platform + boy) and T is the tension in the rope. Would the force of the tension be the same as the reading on the scale?

Mostly I've been unsure how to use that 180N. Then I started thinking that the downward force that the boy exerts on the chair has the same magnitude as the upward normal force that the chair exerts on the boy, giving ƩFy = T + Fn - mboyg = mboyay
Two equations with two unknowns T and a:
2T -55(9.8) = 55a
T + 180 - 40(9.8) = 40a
?
Yes. That all looks fine to me. I got the same thing without first looking at your solution.
 
Last edited by a moderator:

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