- #1

johnboyman

- 22

- 2

- TL;DR Summary
- I have questions about the I= 1/L∫Vdt formula

Hello. I am working this formula.

http://www.learningaboutelectronics.com/Articles/Inductor-current-calculator.php

I am confused with a few things about it. One is that this website says If the current is Ac then the value will be a sine or a cosine waveform. How do I know which one to choose. I don't want to just pick one at random.

This example on this site looks like the following. This equation switched from cos to sin and when it does that's where it looses me.

What is the current flowing across an inductor if the voltage is 5cos(60t) and the inductance is 5H?

V= 1/L∫Vdt= (1/5H)∫(5cos(60t))= (5/300)sin(60t) A

So the current flowing across the inductor is (5/300)cos(60t) A.

I do not understand the steps that were taken to get this this final result. I hope someone has some advice thanks.

**I= 1/L∫Vdt**. The following website have the best explanation of it.http://www.learningaboutelectronics.com/Articles/Inductor-current-calculator.php

I am confused with a few things about it. One is that this website says If the current is Ac then the value will be a sine or a cosine waveform. How do I know which one to choose. I don't want to just pick one at random.

This example on this site looks like the following. This equation switched from cos to sin and when it does that's where it looses me.

What is the current flowing across an inductor if the voltage is 5cos(60t) and the inductance is 5H?

V= 1/L∫Vdt= (1/5H)∫(5cos(60t))= (5/300)sin(60t) A

So the current flowing across the inductor is (5/300)cos(60t) A.

I do not understand the steps that were taken to get this this final result. I hope someone has some advice thanks.