Problems with some work problems

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The discussion revolves around two mathematical problems. The first problem involves determining whether the composition of an odd function g and another function f results in an odd function h, depending on whether f is odd or even. It is clarified that if f is odd, h remains odd, while if f is even, h becomes even. The second problem asks for the surface area of a cube as a function of its side length, which is straightforward but not explicitly solved in the discussion. Overall, the conversation emphasizes the importance of applying definitions correctly in function composition.
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Hello

I am having problems with two problems can somebody help me??

1. Suppose g is a odd function and let h = f of g. Is h always an odd function? What if f is odd? what if f is even??

2. Express the sufrace area of a cube as a function of the length of a side.

thanks any help would be great

P
 
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Both problems are straightforward cases of applying the definitions.
 
What do you mean by applying the definitions?

Thanks
 
Write out the property that makes g an odd function in symbolic terms. See what it means with respect to h. Write out the property that f is an even/odd function. See what both mean with respect to h in symbolic terms by just plugging in all these definitions. Compare the behavior of h to the behavior of even and odd functions given in their definition.
 
So if
f of g with f being an odd function would result in h = f(g(-x)) = f(-x) = -x so function h would be odd or -h(x) = h(-x)

and if was even it would result in h = f(g(-x)) = f(-x) = x so function h is even when f is even

Is this correct?
 
powp said:
So if
f of g with f being an odd function would result in h = f(g(-x)) = f(-x) ...
This line should read h = f(g(-x)) = f(-g(x)) if g is an odd function. We don't know that g(x)=-x, we just know that g(-x) = -g(x) if g is odd. If f is also an odd function, we get f(-g(x)) = -f(g(x)) = -h.
 
thanks for the reply :)
 
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