Product moment of inertia of an inclined section of a beam

AI Thread Summary
The discussion revolves around deriving the product moment of inertia (Ixy) for an inclined section of a beam using integration. The user is struggling with the calculation of the first moment of area necessary for this derivation, despite being able to derive Ixx and Iyy. Another participant suggests a specific formula for Ixy and asks for the integral the user has been working on. The conversation includes clarification on the orientation of the rod and the variables involved in the calculations. The exchange highlights the challenges of integrating over inclined geometries in structural analysis.
emRage
Messages
5
Reaction score
0
Hi guys,

I would like to derive the Ixy equation from simple integration and I can't seem to get the right answer (third equation down the picture). I seem to be able to derive Ixx and Iyy easily but product moment of area requires first moment of area to be calculated and I just don't know how to do that on an inclined section.

Any help would be apprecited on this issue.

Thank you.
 

Attachments

  • un.JPG
    un.JPG
    9 KB · Views: 3,852
  • un1.JPG
    un1.JPG
    5.7 KB · Views: 3,425
Engineering news on Phys.org
Welcome to PF!

Hi emRage! Welcome to PF! :wink:

Is the rod in the x-y plane? And what is t?

ok, you need to prove that Ixy = L3t(sin2θ)/24.

Show us the integral you have for this. :smile:
 
This one I've figured out! :-p

x = cos(theta) . s
y = sin(theta) . s
dA = ds . thickness
limits for s = L/2 and -L/2

Thanks anyway!
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Back
Top