Product of Smooth Manifolds and Boundaries

Click For Summary
SUMMARY

The discussion centers on the theorem in differential topology stating that the product of smooth manifolds \( M_1, \ldots, M_k \) and a smooth manifold with boundary \( N \) results in a smooth manifold with boundary, specifically \( M_1 \times \ldots \times M_k \times N \). The participants emphasize the importance of using charts to demonstrate that the product manifold retains smoothness and boundary characteristics. The approach involves confirming that the product chart is a homeomorphism and ensuring that all product charts are smoothly compatible.

PREREQUISITES
  • Understanding of smooth manifolds and their properties
  • Familiarity with differential topology concepts
  • Knowledge of coordinate charts and homeomorphisms
  • Basic comprehension of boundary conditions in manifolds
NEXT STEPS
  • Study the properties of smooth manifolds in differential topology
  • Learn about the construction and application of coordinate charts in manifold theory
  • Research the concept of smoothly compatible charts and their significance
  • Explore the implications of boundaries in manifold products, particularly in the context of \( H^n \)
USEFUL FOR

Students and researchers in mathematics, particularly those focusing on differential topology, as well as educators seeking to clarify the concepts of smooth manifolds and their boundaries.

Arkuski
Messages
38
Reaction score
0
Sorry guys, I have some differential topology homework, and I may be asking a lot of questions in the next few days.

Problem Statement
Suppose M_1,...,M_k are smooth manifolds and N is a smooth manifold with boundary. Then M_1×..×M_k×N is a smooth manifold with a boundary.

Attempt
Since M_1,...,M_k are smooth manifolds, we are allowed to use the theorem that states that M_1×...×M_kis smooth with charts (U_1×...×U_k,\phi _1×...×\phi _k).

I get the idea that given the smooth manifold $N$ with coordinate chart (U,\psi _i) where \psi _i:N\rightarrow H^n (H^n is the half plane of dimension n), we show that H^n restricts x_i to non-negative values, and then the entire product in consideration will only have one coordinate restricted to non-negative values, signifying the presence of a boundary. I'm just really confused about how to put it into words.
 
Physics news on Phys.org
Arkuski said:
Sorry guys, I have some differential topology homework, and I may be asking a lot of questions in the next few days.

Problem Statement
Suppose M_1,...,M_k are smooth manifolds and N is a smooth manifold with boundary. Then M_1×..×M_k×N is a smooth manifold with a boundary.

Attempt
Since M_1,...,M_k are smooth manifolds, we are allowed to use the theorem that states that M_1×...×M_kis smooth with charts (U_1×...×U_k,\phi _1×...×\phi _k).

I get the idea that given the smooth manifold $N$ with coordinate chart (U,\psi _i) where \psi _i:N\rightarrow H^n (H^n is the half plane of dimension n), we show that H^n restricts x_i to non-negative values, and then the entire product in consideration will only have one coordinate restricted to non-negative values, signifying the presence of a boundary. I'm just really confused about how to put it into words.

The theorem you quoted shows that M_1 \times \cdots \times M_k is a smooth manifold, so it's sufficient to prove the result for M \times N, where M is an arbitrary smooth manifold.

Take an arbitrary point (x,y) \in M \times N. Then take a chart on M centered at x and a chart on N centered at y, work out what the codomain of the product chart is, and confirm that the chart is a homeomorphism.

Then you'll need to show that all product charts are smoothly compatible.
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 36 ·
2
Replies
36
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 39 ·
2
Replies
39
Views
13K